Rebar weight calculator and theoretical weight tables

Reinforcement classes and designations:

A300S, A400S, A500S, A600S, A600, A800K, A800, A1000.
Construction experts know the importance of the initial construction and installation operations when it comes to purchasing reinforcement. Among the rolled metal products of this type, corrugated fittings are in demand. Due to its design features, it provides good adhesion to reinforced concrete structures, making them strong and durable. These qualities are especially important when constructing foundations.

Corrugated fittings or otherwise products of a periodic profile: these are steel rods with stiffeners. The ribs can have a certain height relative to the base of the rod, be crescent-shaped or segmental in shape. The rod can be round or square or any other shape.

Since this type of steel reinforcement is often used in manufacturing processes, its weight and quantity must be constantly calculated. This is a routine process carried out by metal purchasers to prepare estimates for all types of work. Until recently, employees had to arm themselves with a calculator and make calculations using formulas or tables.

Now the situation has changed dramatically, since information technology has made it possible to develop a reinforcement calculator, which with high accuracy determines the weight of the reinforcement, as well as the diameter of the reinforcement.

Information on the purpose of the calculator

Online calculator for monolithic slab foundation (slabs)

designed for calculating dimensions, formwork, quantity and diameter of reinforcement and volume of concrete required for arranging this type of foundation for houses and other buildings. Before choosing the type of foundation, be sure to consult with specialists whether this type is suitable for your conditions.

All calculations are performed in accordance with SNiP 52-01-2003 “Concrete and reinforced concrete structures”, SNiP 3.03.01-87 and GOST R 52086-2003

Slab foundation (ushp) is a monolithic reinforced concrete foundation laid under the entire area of ​​the building. Has the lowest ground pressure among other types. It is mainly used for light buildings, since with increasing load the cost of this type of foundation increases significantly. With shallow depth, on fairly heaving soils, it is possible to uniformly raise and lower the slab depending on the time of year.

It is imperative to have good waterproofing on all sides. Insulation can be either sub-foundation or located in the floor screed, and most often extruded polystyrene foam is used for these purposes.

The main advantage of slab foundations is their relatively low cost and ease of construction, since, unlike a strip foundation, there is no need to carry out a large amount of excavation work. Usually it is enough to dig a pit 30-50 cm deep, at the bottom of which a sand cushion is placed, as well as, if necessary, geotextiles, waterproofing and a layer of insulation.

It is imperative to find out what characteristics the soil under the future foundation has, as this is the main deciding factor when choosing its type, size and other important characteristics.

When filling out the data, pay attention to the additional information with the Additional information sign

The following is a complete list of calculations performed with a brief description of each item. You can also ask your question using the form in the right block.

Features of the calculator

A tool designed to perform accurate calculations is a program configured to produce an accurate result when data on corrugated reinforcement is entered into the system. This data is usually provided by the product manufacturer or can be found in tables and descriptions included in the standards.

To determine the weight of corrugated reinforcement or calculate how many meters in a ton, you need to enter the data:

• type of material: metal;
• type of assortment: fittings;
• standard defining the rules for production and quality of products: GOST 5781-82, GOST R 52544-2006;
• diameter of corrugated fittings.

After entering the data, the electronic tool will immediately begin calculating the specified values, and then display the results in real time. They can be safely used for purchasing materials, since the calculator is configured for highly accurate work and errors are practically eliminated.

For wholesale buyers and suppliers, the calculator is a reliable assistant when drawing up estimates. It allows you to accurately calculate materials and save money on their purchase.

How to calculate the weight of one linear meter of steel reinforcement?

It is necessary to multiply the cross-sectional area of ​​reinforcement of a given diameter by the density of steel, which is usually taken to be 7.85 g/cm³. The easiest way to find the circular cross-sectional area is through the diameter. So, for 12 mm reinforcement, the weight of one meter is:

M = S·ρ = π·d²/4·7.85 = 3.14·0.012²/4·7.85 = 0.8874 kg. In the table we find that one meter of 12 mm reinforcement weighs 0.888, this confirms the good accuracy of the calculation method.

To find out how many meters of 12 mm thick reinforcement are in a ton, you need to divide 1000 kg by the weight of one linear meter of 0.888. The result will be 1126 meters.

To answer the question of how many meters of reinforcement 8 mm thick are in a ton, we find it in the table or calculate the weight of one linear meter (0.395 g/cm³) and divide 1000 kg by it. Answer: 1000/0.395 = 2532 m. We can also solve your need for designing private houses in St. Petersburg.

Final settlement

The number of tons of reinforcement of the required diameter and class for your required linear meters can be calculated using the inverse formula.

Let's say you need 22,000 m of A400 class reinforcing steel with a diameter of 10 mm. To do this, you need to multiply the required footage by the weight of 1 m of this profile: 22,000 x 0.617 = 13,574 kg = 13,574 t + 6% = 14,388 t.

Now you can safely select the coils using the tags, which indicate how much reinforcement is in the coil in tons.

Profiles of any class are calculated in the same way. So, for example, for the same number of meters of 12 mm reinforcement, the required number of tons will be 19.536 tons + 6% = 20.708 tons.

All you have to do is choose the option that is beneficial for yourself, taking into account the cost, reliability and strength of the planned structure. And we guarantee accurate and timely shipment of products.

General information on the calculation results

• Slab perimeter

— Length of all sides of the foundation

• Slab base area

— Equals the area of ​​the required insulation and waterproofing between the slab and the soil.

• Lateral surface area

— Equal to the insulation area of ​​all sides.

• Concrete volume

— The volume of concrete required to pour the entire foundation with the given parameters. Since the volume of concrete ordered may differ slightly from the actual one, as well as due to compaction during pouring, it is necessary to order with a 10% reserve.

• Concrete weight

— The approximate weight of concrete based on average density is indicated.

• Load on soil from foundation

— Distributed load over the entire support area.

• Minimum diameter of reinforcing mesh bars

— Minimum diameter according to SNiP, taking into account the relative content of reinforcement from the cross-sectional area of ​​the slab.

• Minimum diameter of vertical reinforcement bars

— Minimum diameter of vertical reinforcement bars according to SNiP.

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• Grid cell size

— Average cell size of the reinforcement cage mesh.

• Amount of reinforcement overlap

— When fastening sections of rods with overlap.

• Total length of reinforcement

— The length of all reinforcement for tying the frame, taking into account the overlap.

• Total weight of reinforcement

— Weight of the reinforcement cage.

• Formwork board thickness

— Design thickness of formwork boards in accordance with GOST R 52086-2003, for given foundation parameters and at a given support spacing.

• Number of boards for formwork

— The amount of material for formwork of a given size.

To calculate the USP, it is necessary to subtract the volume of the insulation being laid from the volume of the calculated concrete.

How much do reinforcing bars weigh?

Reinforcement is metal rods that are used to strengthen concrete monolithic structures. The construction of the frame requires an accurate calculation of the quantity and mass of the required material already at the stage of drawing up project documentation in order to accurately determine the cost of the upcoming construction.

Determination of basic quantities

Specific gravity is the mass of 1 linear meter of iron wire. Weighing is the easiest way to determine. The procedure is carried out on industrial scales, because special equipment does not exist. For weighing, select a metal rod and measure its length. Then the value indicated on the scales is divided by the length and the weight of a meter of reinforcement of a given diameter is obtained.

The second method is more complicated; it is used if suitable scales are not available. First, measure the diameter (D) of the rod. Then the cross-sectional value is calculated using the formula: S=3.14*D/2*D/2. The resulting value is multiplied by the steel density of 7850 kg/m3. This is precisely the value fixed by GOST for construction calculations. As a result of the calculations, the desired specific gravity is obtained.

The parameters used in the calculations must be reduced to common units of mass measurements, which are specified in GOST standards:

• kilograms (kg);
• meters (m).

All of the above calculations apply to a smooth type of surface that has a regular round cut. For products with a grooved profile, it is necessary to measure one diameter along the protrusions, the second - between them, and then find the average value.

The results of calculations carried out independently often differ from the data in the tables. If the deviations are insignificant for smooth wire, then for corrugated rods the error can be much greater. This is explained by the fact that the calculations are greatly simplified. The weight of the reinforcement given in the standards was calculated taking into account the specifics of the corrugation (size, pitch, longitudinal edge).

Calculation according to standards

The first step is always the preparation of project documentation. Experts determine the required pattern, as well as the diameter. In private construction, as a rule, wire with a cross section of 12 and 14 mm is used. Next, materials are purchased based on design calculations. Keep in mind that wire is measured in linear meters and sold by weight.

The mass of steel for purchase is determined by multiplying the total length of the circuit by the weight of 1 linear meter of reinforcement. The rods are sold in coils, so it is possible to cut the rods to the required length immediately upon purchase.

How much does reinforcement of different diameters weigh?

The standard ratio of mass and diameter is regulated by GOST 5781-82.

Using the table data is very simple: first find the size in the first column, and then find how much 1 linear meter weighs.

Online stores often post special calculators. You need to enter the diameter in a special window, and all the required values ​​will be calculated automatically.

Author: Valentin Tokarev